1000w dc 12v/24v/48V to ac 220V 230V 240V power inverter

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Price:$82.50 - $95.37

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Product Overview

Description



1000w dc 12v/24v/48V to ac 220V 230V 240V power inverter


Product Paramenters




Products Description


MODEL
FS600
FS1000
FS1500
FS2000
FS2500
FS3000
FS3500
FS4000
DC Voltage
12V/24V/48V
Output
AC Voltage
100V/110V/120V/220V/230V/240V
Rated Power
1200W
2000W
3000W
4000W
5000W
6000W
7000W
8000W
Surge Power
Load 120~150%(3min.);4000W(3sec;resistive)
Waveform
Pure Sine Wave(THD<3%)
Frequency
50Hz/60Hz ±0.05%
Power Factor Allowed
COSθ-90°~COSθ+90°
Standard Receptacles
USA/British/Franch/Schuko /UK/Australia/Universal etc. optional
LED Indicator
Green for power on, red for faulty status
USB port
5V 2.1A
LCD display
voltage, power, protection status ( optional)
Remote controller
CRW80 / CR80 / CRD80 optional
Efficiency(Typ.)
89%~93%
Over Load
Shut down output voltage , restart to recover
Over Temperature
Shut down output voltage , recover automatically after temperature goes down
Output Short
Shut down output voltage , restart to recover
Earth Fault
Shut off o/p when the load has electrical leakage
Soft Start
Yes, 3-5 Seconds
Environment
Working Temp.
0~+50℃
Working Humidity
20~90%RH non-condensing
Storage Temp.&Humidity
-30~+70℃,10~95%RH
Others
Dimension(L×W×H)
281.5×173.6×103.1mm
313.5×173.6×103.1mm
325.2×281.3×112.7mm
325.2×281.3×112.7mm
442.2×261.3×112.7mm
442.2×261.3×112.7mm
533.2×261.3×112.7mm
533.2×261.3×112.7mm
Packing
2.1KG
2.9KG
5.2kg
5.5kg
7.3kg
8kg
8.5kg
8.5kg
Cooling
Load control fan or by thermal control fan
Application
Home and Office appliances,Portable Power Equipment,Vehicle,Yacht and Off-Gid Solar
power systems…etc.


Company Profile






Certifications




Our Advantages






FAQ


1,Q:Why your quotation is higher than other suppliers?
A:In the Chinese market, many factories sell low-cost inverters, which are actually assembled by small unlicensed
workshops,largely to cut costs and use substandard components for assembly. There's a major security breach SOLARWAY is a
professinonal power inverter R & D, manufacturing and sales enterprises, we deeply cultivated the German market for more than 10
years, each year exports about 50,000-100,000 power inverter to Germany and its surrounding markets Our product quality is worthy
of your trust!
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2,Q:How many categories does it have according to the output waveform ?
A:Type one: our NM and NS series Modified Sine Wave inverter, which uses PWM pulse width modulation to generate modified sine
wave. Due to the usage of intelligent dedicated circuit and high power field effect tube, it greatly reduces the power loss and
increases the soft-start function, effectively ensuring the reliability of the inverter. If the power quality is not highly
demanded, it is able to meet the needs of most electrical equipment. But it still exists 20% harmonic distortion problems when
running sophisticated equipment, can also cause high-frequency interference to radio communications equipment. This kind of
inverter can meet the basic needs of most of our power, high efficiency, small noise, moderate price, and thus become the
mainstream products in the market.
Type two: our NP, FS, NK series Pure Sine Wave inverter, which adopts isolated coupling circuit design, high efficiency, high
stability of the output waveform, high-frequency technology, small in size, suitable for all kinds of load, can be connected to
any common electrical devices and inductive load devices (such as refrigerators, electric drill, etc.) without any interference
(eg: buzz and TV noise). The output of pure sine wave inverter is the same as the grid tie power we daily used, or even better,
because it does not exist grid tie electromagnetic pollution..
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3,Q:What is a resistive load appliances?
A:Generally speaking, appliances like mobile phones, computers, LCD TVs, incandescents, electric fans, video broadcast, small
printers, electric mahjong machines, rice cookers etc. All belong to resistive loads. Our modified sine wave inverters can drive
them successfully.
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4,Q:What is the inductive load appliances?
A:It refers to the application of electromagnetic induction’s principle, produced by high-power electrical products, such as motor
type, compressors, relays, fluorescent lamps, electric stove, refrigerator, air conditioner, energy saving lamps, pumps, etc.These
products’power are far more than the rated power (about 3-7 times) when start. So only pure sine wave inverter is available to
them.
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5,How to choose suitable inverter ?
If your load is resistive loads, such as: bulbs, you can choose a modified wave inverter. But if it is inductive loads and
capacitive loads, we recommend using pure sine wave inverter. For example: fans, precision instruments, air conditioner,
fridge,coffee machine, computer, and so on. Modified wave can be started with some inductive loads, but effect for load using
life, because capacitive loads and inductive loads need highquality power.
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6,How do I choose the size of the inverter ?
Different types of load demand for power are different. You can view the load power values to determine the size of the inverter.
Notice: resistive load: you can choose the same power as the load. Capacitive loads: according to the load, you can choose 2-5
times power. Inductive loads: according to the load, you can choose 4-7 times power.
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7,How connection between batteries and an inverter ?
We usually believe that cables connecting battery terminal to inverter shorter is better. If you are just standard cable should be
less than 0.5M, but should correspond to the polarity of the batteries and inverter-side outside. If you want to lengthen the
distance between battery and inverter, please contact us and we will calculate the recommended cable size and length. Due to long
distances using a cable connection, there will be a reduced voltage, which means that the inverter voltage would be far below the
battery terminal voltage, this inverter will appear under voltage alarm conditions.
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8,How to calculate the load of working hours requires configuration of the battery size ?
We will usually have a formula to calculate, but it is not hundred percent accurate, because there is also the battery's
condition, the old batteries have some loss, so this is only a reference value: Work hours = battery capacity * battery voltage
*0.8/load power (H= AH*V*0.8/W)




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