1000 Вт, модифицированный синусоидальный инвертор солнечной энергии, преобразователь от сети 12 В постоянного тока в 120 В переменного тока 220 В

Product Overview

Description

1000w modified sine wave microtek inverter Modified Sine Wave Solar Power Inverter Off grid converter  Manufacturer

Solarway is a Sino-Germany joint venture, our engineers mainly from Germany that focusing on developing, designing and manufacturing products, we have after-selling service center in Germany. 

Solarway is committed to providing proactive service, innovative technology and total quality assurance since established.Welcome to contact us and visit our factory.

 

 

 

1000w Modified Sine Wave Solar Power Inverter Off grid converter 12V DC to AC 120V 220V Wandler 

 

Features:

 Modified sine wave output

 High surge power

 Fully electric protection: Lower voltage alarm & shutdown, over voltage, earth fault, short circuit, over load, soft start, over temperature, polarity reverse

 Factory default color for case- BLACK, the color can be customized according to client's requirements

Model	NM1000
Rated power	1000W
Surge power	2000W
DC input voltage	12V or 24V
AC output volatge	100-120V / 200-240V
AC output frequency	50/60Hz
Out wavefom	Modified sine wave
Lower voltage alarm	10.5±0.5V for 12V battery bank(*2 for 24V,*4 for 48V)
Lower voltage cut off	10±0.5V for 12V battery bank(*2 for 24V,*4 for 48V)
Over voltage cut off	15.5±0.5V for 12V battery bank(*2 for 24V,*4 for 48V)
Over temperatuer cut off	ambient temperature-10℃+40℃/Internal temperature 55℃-65℃
Polarity reverse protection	by fuse open
Cooling fan	control by load/temperature
Inverter efficiency	>90%
Warranty	2 years

 

 

 

 

 

 

 

 

 

1,Q:Why your quotation is higher than other suppliers?
A:In china market, There are many factories selling low-cost inverters, which is actually some assembled small unlicensed workshops, it crudely, to reduce costs and use of substandard components for assembly, and some factories sells less power. For example real power is 600w but write 1000W or more. there is a very big security risk! In order to protect the personal and property safety, please do not covet low price, be sure to choose a reliable inverter!
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2,Q:How many categories does it have according to the output waveform ?
A:Type one: our NM and NS series Modified Sine Wave inverter, which uses PWM pulse width modulation to generate modified sine wave. Due to the usage of intelligent dedicated circuit and high power field effect tube, it greatly reduces the power loss and increases the soft-start function, effectively ensuring the reliability of the inverter. If the power quality is not highly demanded,  it is able to meet the needs of most electrical equipment. But it still exists 20% harmonic distortion problems when running sophisticated equipment, can also cause high-frequency interference to radio communications equipment. This kind of inverter can meet the basic needs of most of our power, high efficiency, small noise, moderate price, and thus become the mainstream products in the market.
   Type two: our NP, FS, NK series Pure Sine Wave inverter, which adopts isolated coupling circuit design, high efficiency, high stability of the output waveform, high-frequency technology, small in size, suitable for all kinds of load, can be connected to any common electrical devices and inductive load devices (such as refrigerators, electric drill, etc.) without any interference (eg: buzz and TV noise). The output of pure sine wave inverter is the same as the grid tie power we daily used, or even better, because it does not exist grid tie electromagnetic pollution..
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3,Q:What is a resistive load appliances?
A:Generally speaking, appliances like mobile phones, computers, LCD TVs, incandescents, electric fans, video broadcast,  small printers, electric mahjong machines, rice cookers etc. All belong to resistive loads. Our modified sine wave inverters can drive them successfully.
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4,Q:What is the inductive load appliances?
A:It refers to the application of electromagnetic induction’s principle, produced by high-power electrical products, such as motor type, compressors, relays, fluorescent lamps, electric stove, refrigerator, air conditioner, energy saving lamps, pumps, etc. These products’power are far more than the rated power (about 3-7 times) when start. So only pure sine wave inverter is available to them.
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5,How to choose suitable inverter ?

 

If your load is resistive loads, such as: bulbs, you can choose a modified wave inverter. But if it is inductive loads and capacitive loads, we recommend using pure sine wave inverter. For example: fans, precision instruments, air conditioner, fridge, coffee machine, computer, and so on. Modified wave can be started with some inductive loads, but effect for load using life, because capacitive loads and inductive loads need highquality power.

 

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6,How do I choose the size of the inverter ?

Different types of load demand for power are different. You can view the load power values to determine the size of the inverter. Notice: resistive load: you can choose the same power as the load. Capacitive loads: according to the load, you can choose 2-5 times power. Inductive loads: according to the load, you can choose 4-7 times power.

 

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7,How connection between batteries and an inverter ?

We usually believe that cables connecting battery terminal to inverter shorter is better. If you are just standard cable should be less than 0.5M, but should correspond to the polarity of the batteries and inverter-side outside. If you want to lengthen the distance between battery and inverter, please contact us and we will calculate the recommended cable size and length. Due to long distances using a cable connection, there will be a reduced voltage, which means that the inverter voltage would be far below the battery terminal voltage, this inverter will appear under voltage alarm conditions.

 

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8,How to calculate the load of working hours requires configuration of the battery size ?

We will usually have a formula to calculate, but it is not hundred percent accurate, because there is also the battery's condition, the old batteries have some loss, so this is only a reference value: Work hours = battery capacity * battery voltage *0.8/load power (H= AH*V*0.8/W)

 

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